Question

$\sqrt{2 + \leqsl} 1 \div \sqrt{2 }$
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Answer 1

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$\frac{ \sqrt{2 + 1} }{ \sqrt{2} }$

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rationalize the denominator...

$\frac{( \sqrt{2 + 1})( \sqrt{2} )}{ \sqrt{2} \times \sqrt{2} }$

$\frac{ \sqrt{6} }{2}$

you can simplify further by placing the value of √6....but you can also leave till here...

=> mark as brainliest....