Question

$\sqrt{2} \: \: proved \: the \: inrattional \: nomber$

Answer 1

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qυєѕтισи:

Prove that $\sqrt{2 }$ is a irrational number

αnѕwєr :

Let us assume that $\sqrt{2}$ is a rational number....

Let a,b are the prime numbers....

Therefore,

We get

$\sqrt{2} = \frac{a}{b}$

If we transpose $\sqrt{2} \: on \: the \: rhs \: we \: get$

$b = \sqrt{2} a$

But the contadict that facts that
$\sqrt{2} a$ is an irrational number.....

Therefore,
$\sqrt{2}$ is an irrational number.....

$hence \: proved$
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