Question

$\sqrt{2 {x}^{2 } - 2x + 1 } - 2x + 3$


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Answer 1

Answer:

$\\\sqrt{2x^2-2x+21}-2x+3=0\\\\\sqrt{2x^2-2x+21}=2x-3\\\\2x^2-2x+21=(2x-3)^2\\\\2x^2-2x+21=4x^2-12x+9\\\\4x^2-12x+9-2x^2+2x-21=0\\\\2x^2-10x-12=0\\\\2(x^2-5x-6)=0\\\\x^2-5x-6=0\\\\x^2+x-6x-6=0\\\\x(x+1)-6(x+1)=0\\\\(x+1)(x-6)=0$

$x+1=0$                 $x-6=0$

$x=-1$                     $x=6$

∴ x = -1 or x = 6

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