Math, asked by sanjeevrao123456789, 7 months ago


 \sqrt{3 {  }^{2} }  + 10x - 8 \sqrt{3}  = 0 \: solve \: by \: quadratic \: formula

Answers

Answered by Anonymous
2

Correct Question:

★√3x²+10x-8√3=0

=> x =-b±√b²-4ac/2a

=> x =-10±√10²-4×√3×8√3/2√3

=>x =-10±√100-96/2√3

=>x =-10±√4/2√3

=>x =-5±1/√3

.°. x = -23,-4/3.

Answered by Neelima2324
0

Answer:

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