Question

$\sqrt[3]{4} \times \sqrt{2}$
solve this plz as soon as possible

Answer 1

2^(2/3+1/2)
2^(7/6).
........

Answer 2

$\sqrt[3]{4}$ × $\sqrt{2}$
$= 4^{\frac{1}{3}}$ × $2^{\frac{1}{2}}$
$= (2^2)^{\frac{1}{3}}$ × $2^{\frac{1}{2}}$
$= 2^{\frac{2}{3}}$ × $2^{\frac{1}{2}}$
$= 2^{\frac{2}{3} + \frac{1}{2}}$
$= 2^{\frac{4 + 3}{6}}$
$= 2^{\frac{7}{6}}$
$= \sqrt[6]{2^7}$
$= \sqrt[6]{128}$
$= 2 \sqrt[6]{2}$

Hope this will be helpful.