![\sqrt[3]{64} + {2}^{3} = \sqrt[3]{64} + {2}^{3} =](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B64%7D+%2B++%7B2%7D%5E%7B3%7D++%3D+)
Answers
Answered by
0
Answer:
³√64+2³
4+8=12
hope it helps you and don't forget to follow mè
Answered by
1
Answer:
4+8= 12
Step-by-step explanation:
Hope it will helpful...
Similar questions