Question

$\sqrt[3]{\frac{y^{5} }{27y^2} }$

Answer 1

Step-by-step explanation:

$\sqrt[3]{ \frac{ {y}^{5} }{27 {y}^{2} } } \\ = \sqrt[3]{ \frac{ {y}^{3} }{27 } } \: \: \: \: \: \: \: \: \: \\ \: \: \: \ = \sqrt[3]{ \frac{ {y \times y \times y} }{ 3 \times 3 \times 3 } } \\\ = \frac{ {y} }{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Hope you get your answer!!

Please mark me as brainliest!!

Answer 2

Question :- $\sqrt[3]{\frac{y^{5} }{27y^{2}}}$

Solution :-

$\purple\longmapsto\footnotesize \sqrt[3]{\frac{y^{5}}{27y^{2}}}\\\\\purple\longmapsto\footnotesize\: \sqrt[3]{\frac{ \cancel{y^{5}}}{27 \cancel{y^{2}}}}\\\\ \purple\longmapsto\footnotesize \sqrt[3]{\frac{y^{3}}{27}} \\ \\ \purple\longmapsto\footnotesize \: (\frac{ {y}^{3}}{27})^{ \frac{1}{3} } \\ \\ \purple\longmapsto\footnotesize \: (\frac{ {y}^{3}}{ {3}^{3} })^{ \frac{1}{3} } \\ \\ \purple\longmapsto\footnotesize \: ((\frac{y}{3})^{ \cancel3})^{ \frac{1}{ \cancel3} } \\ \\ \purple\longmapsto\footnotesize \: \frac{y}{3}$

Learn more :-

if a nine digit number 260A4B596 is divisible by 33, Then find the number of possible values of A.

https://brainly.in/question/32686002

if n is an integer such that 1nn352 is a six digit number

https://brainly.in/question/26617043