Question

$\sqrt{3} + \sqrt{2} \div \sqrt{3} - \sqrt{2}$
conjugate

Answer 1

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Answer 2

Solution:-

$\sqrt{3} + \sqrt{2} \div \sqrt{3} - \sqrt{2} \\ \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ 5 + 2 \sqrt{6} \: ans$