Math, asked by antresh8, 10 months ago


 \sqrt{3  \sqrt{3 \sqrt{3 \sqrt{3 \sqrt{3} } } } }

Answers

Answered by nicoceb5
0

Answer:

\sqrt[32]{3^{31} }

Step-by-step explanation:

\sqrt{3\sqrt{3}  }  = \sqrt{\sqrt{3^{3} } }  = \sqrt[4]{3^{3} } and so on... you insert the radicand in the previos root and multiply the roots (multiply their radical)

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