Question

$\sqrt{3} \sqrt{6} \sqrt{9} \sqrt{12} ........ find \: ap \: and \: common \: difference$
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Answer 1

Answer:

No

Given series √3,√6,√9,√12 ,...is not an A.P

Explanation:

Given series :

√3,√6,√9,√12,...

Find Difference between two

consecutive terms :

a2-a1 = √6 - √3

a3-a2 = √9-√6 = 3-√6

a4-a3 = √12-√9 = 2√3-3

a2-a1 ≠ a3-a1≠a4-a3

________________________

we know that,

Difference between any

two consecutive terms are equal in A.P

_________________________

Therefore,.

Given series not an A.P

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Answer 2

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