![\sqrt[3 \sqrt{} ]{64} =](https://tex.z-dn.net/?f=+%5Csqrt%5B3+%5Csqrt%7B%7D+%5D%7B64%7D++%3D+ "\sqrt[3 \sqrt{} ]{64} =")
find the sum?
apm43:
first, √64=8. then Quebec root of 8=2.....that's y dis is solved....... :)
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HEYA ❣️
³√64=4
AS 4×4×4=4³=64
ur ans is wrong...... dude
√64=8. then Québec root of 8=2
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