Math, asked by preetiahir, 1 year ago


 \sqrt{3 \:} x {}^{2}  - 2 \sqrt{2} x - 2 \sqrt{3}

Answers

Answered by Harshit1503
1
√3x²-3√2x+√2x-2√3
√3x(x-√6)+√2(x-√6)
(√3x+√2)(x-√6)
Answered by rakeshmohata
1
Hope u like my process
======================
 \sqrt{3}  {x}^{2}  - 2 \sqrt{2} x - 2 \sqrt{3}  \\   \\ =  \sqrt{3 }x^{2}  - 3 \sqrt{2} x +  \sqrt{2}  x - 2 \sqrt{3}  \\  \\  =  \sqrt{3} x(x -  \sqrt{6} ) +  \sqrt{6} (x -  \sqrt{6} ) \\ \\   = (x -  \sqrt{6} )( \sqrt{3} x +  \sqrt{6} )
Hope this is ur required answer

Proud to help you
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