Question

$\sqrt{3 {x }^{2} } - 8x + 4 \sqrt{3}$
​

Answer 1

Answer :-

→ x = 2/√3 or 2√3 .

Step-by-step explanation :-

We have,

→ √3x² - 8x + 4√3 = 0 .

→ √3x² - 6x - 2x + 4√3 = 0 .

→ √3x( x - 2√3 ) - 2( x - 2√3 ) = 0 .

→ ( √3x - 2 )( x - 2√3 ) = 0 .

→ √3x - 2 = 0 or x - 2√3 = 0 .

\therefore∴ x = \frac{2}{\sqrt{3}}

3

2

or x = 2 \sqrt{3}2

3

.

Hence, it is solved .