Math, asked by smritakumari1986, 7 hours ago


( \sqrt{32} ) {}^{x} \div 2 {}^{y + 1 }  =1 and \: 8 {}^{y}  - 16 {}^{4 - x |2 } = 0
find x and y​

Answers

Answered by sadikshaikh226023
0

Answer:

22÷$32÷$35/%35^323=3%%4/%54/÷$^%/53355

Similar questions