Question

$\sqrt{36} + \sqrt{288} \div 2 + 4 \sqrt{2}$
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Answer 1

Step-by-step explanation:

√36+√288÷2+4√2

=>6+12√2+4√2

=>6+16√2

Answer 2

$\frac{ \sqrt{36} + \sqrt{288} }{2 + 4 \sqrt{2} } \\ \\ = \frac{6 + 12 \sqrt{2} }{2 + 4 \sqrt{2} } \\ \\ = \frac{ \cancel2(3 + 6 \sqrt{2} )}{ \cancel2(1 + 2\sqrt{2} )} \\ \\ = \frac{3 + 6 \sqrt{2} }{1 + 2 \sqrt{2} }$

Or, in decimals, it can be expressed as:

$\frac{3 + 6 \sqrt{2} }{1 + 2 \sqrt{2} } \\ \\ = \frac{3 + 6(1.41)}{1 + 2(1.72)} \\ \\ = \frac{11.48}{4.46} \\ \\ = 2.57$

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