Question

$\sqrt{3x {}^{2} - 2 } = (2x - 1)$
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Answer 1

Answer:

$\sqrt{3x^2-2}=2x-1$

Squaring both sides,

$(\sqrt{3x^2-2})^2=(2x-1)^2$

$3x^2-2=4x^2-4x+1$

$x^2-4x=-3$

$x^2-4x+3=0$

$x^2-x-3x+3=0$

$x(x-1)-3(x-1)=0$

$(x-3)(x-1)=0$

$x-3=0$

$x=3$

$x-1=0$

$x=1$

$x=1,3$