Question

$\sqrt{3x {}^{2} } - 2 \sqrt{2x} - 2 \sqrt{3 = 0}$
solve for the x​

Answer 1

Step-by-step explanation:

√3x^2 -2√2x-2√3=0, the given equation is quadratic equation. It's form is ax^2+bx+c=0. Here, a= √3, b= -2√2 , c= -2√3 . Hence x= -b±√(b^2-4ac)/2a. x= 2√2± √(8 +24)/2√3. x= 2√2± √(32)/2√3 = x= (2√2±4√2)/2√3, x= (2√2+4√2)/ 2√3 and ( 2√2-4√2) / 2√3 . We get √6 and -√6/3. Hence the values of x are √6 and -√6/3, Hope this helps you.