Math, asked by geniusreet, 11 months ago


 \sqrt[4]81 +  \sqrt[3]216 - 15 \sqrt[5]32 +  \sqrt{225} {?}

Answers

Answered by Prakhar2908
1

Answer:

= 0

Step-by-step explanation:

 \sqrt[4]{81}  +  \sqrt[3]{216}  + - 15 \sqrt[5]{32}  +  \sqrt{225}

(81)^1/4 + (216)^1/3-15(32)^1/5+(225)^1/2

(3^4)^1/4 + (6^3)^1/3 -15(2^5)^1/5 + (225)^1/2

3+6-20+15

20-20

0

Concepts used :

(a^n)^m = a ^ mn

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