Math, asked by dilulaila, 9 months ago


 \sqrt[4]{}  \sqrt[3]{2 {}^{2} }

Answers

Answered by HariesRam
11

Answer:

 \sqrt[4]{} \sqrt[3]{2 {}^{2} }

= \sqrt[4]{} \sqrt[3]{4}

= 1.1

Answered by Anonymous
43

\huge{\balck{\boxed{ \sqrt[4]{} \sqrt[3]{2 {}^{2} } = \sqrt[4]{} \sqrt[3]{4}}}}}}}}}}}}}}}}

\large\boxed{\fcolorbox{First}{\:Let\:us\:solve\:for\:\sqrt[3]{4}}}

∛4 = 1.587

\large\boxed{\fcolorbox{Now}{\:Let\:us\:solve\:for\:\sqrt[4]{1.587}}}

TO SOLVE THIS WE SHOULD KNOW ABOUT De Moivre's Theorem

\large{\green{\boxed{\sqrt[n]{1} = cos\dfrac{2k\pi}{n} + sin\dfrac{2k\pi}{n} \, i}}}}}}}}}}}}}}}

\large{\green{\boxed{\sqrt[n]{-1} = cos\dfrac{(2k+1)\pi}{n} + sin\dfrac{(2k+1)\pi}{n} \, i}}}}}}}}}}}}}}}

\huge\boxed{\sqrt[4]{1.587}  = 1.12239115}}}

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