Question

×=
$\sqrt{4 + \sqrt{4 - \sqrt{4 + \sqrt{4 - \sqrt{4 + \ } } } } }$
then find the value of 2x- 1​

Answer 1

The value of 2x-1 = 3

Step-by-step explanation:

√4 can be written as √2²

The root and the square is cancelled. Hence 2will be remaining.

By the above values we can write as =

2+2-2+2-2 = 6-4 = 2

We got x = 2

We have to find 2x-1

2(2)-1 = 4-1 = 3

Hence,

The value of 2x-1 = 3