Question

$\sqrt{5} \geq \sqrt{4}$

Answer 1

Step-by-step explanation:

$\sqrt{5} > \sqrt{4} \\ On \: squaring \: both \: sides ,\:we \: get ,\\ \sqrt{ ({5}^{2} )} > \sqrt{ ({4}^{2}) } \\ = 5 > 4</em><strong>(Hence, \: Proved)$

Answer 2

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$$\begin{lgathered}\sqrt{5} > \sqrt{4} \\ On \: squaring \: both \: sides ,\:we \: get ,\\ \sqrt{ ({5}^{2} )} > \sqrt{ ({4}^{2}) } \\ = 5 > 4(Hence, \: Proved)\end{lgathered}$$