![\sqrt[6]{12} \sqrt[6]{12}](https://tex.z-dn.net/?f=+%5Csqrt%5B6%5D%7B12%7D+)
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Here, we have to find .
So, √12 × 6 × 6
= √12 × 36
= √432
Since √432 is not a perfect square, it can be simplified and written as .
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