Question

$\sqrt{7 + \sqrt{40} }$
simplyfy this ...​

Answer 1

$= \sqrt{7 + \sqrt{40} }$

$= \sqrt{7 + 2 \sqrt{10 } } + \frac{1}{ \sqrt{7 + 2 \sqrt{10 } } }$

$= \sqrt{( \sqrt{2 } + \sqrt{5} ^{2} } + \frac{1}{ \sqrt{( \sqrt{2 } + \sqrt{5} ^{2} } }$

$= \sqrt{2} + \sqrt{5} + \frac{1}{ \sqrt{2} + \sqrt{5} }$

$= \sqrt{2} + \sqrt{5} + \frac{ \sqrt{2} - \sqrt{5} }{ - 3}$

$= \frac{1}{ - 3}$

$= - 3$

Answer 2

Step-by-step explanation:

1/-3 = -3

hope it helps you