Question

$( \sqrt{7} + \sqrt{6} ) {}^{2}$
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Answer 1

Step-by-step explanation:

$( { \sqrt{7)} }^{2} + ( { \sqrt{6)} }^{2} - 2 \times \sqrt{6 \times 7} = 7 + 4 - 2 \sqrt{42} = 11 - 2 \sqrt{42}$

that's is your answer