Question

$\sqrt{7} {x}^{2} - 6x - 13 \sqrt{7 } = 0$
Solve the quadratic equation​

Answer 1

Answer:

√7x²-6x-13√7=0

√7x²-13x+7x-13√7=0

(√7x²-13x)+(7x-13√7)=0

x(√7x-13)+√7(√7x-13)=0

(√7x-13)(x+√7)=0

(√7x-13=0)(x+√7=0)

x=13/√7 and x=(-√7)