Math, asked by prashantmal, 9 months ago

\sqrt{7} x^{2} -6x-13\sqrt{7}

Answers

Answered by ambarkumar1
0

= √7x² – 6x – 13√7

= √7x² – 13x + 7x – 13√7

= x ( √7x – 13 ) + √7 ( √7x – 13 )

= ( x + √7 ) ( √7x – 13 )

Answered by mahipallavi0096
1

Answer:

Step-by-step explanation:

= √7x² – 6x – 13√7

= √7x² – 13x + 7x – 13√7

= x ( √7x – 13 ) + √7 ( √7x – 13 )

= ( x + √7 ) ( √7x – 13 )

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