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Answer:
Answer is underroot[(9+y^2)/9]
Step-by-step explanation:
sec{tan^-1 (-y/3)}
tan^-1 (-y/3) be theta
sec(theta) = underroot 1+tan^2 theta
=underroot 1+y^2/9
So sec theta = underroot[(9+y^2)/9]
Answered by
1
Answer:
hey Shivaa
you haven't gave reply to my birthday wish and you haven't wished me on my birthday , leave it don't wish me atleast reply thank you for the birthday wish that I message you i think you have moved on . ok but I will wait for you till July 31 . if you won't reply me then I will never ever in my life talk to you ok .
I will be waiting for you .
I hope you message me before only
btw sorry Yrr for my mistake or harm that I given to you
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