Question

$tan(26) \div \cot(64 )$
Evaluate

Answer 1

$\frac{ \tan(26) }{ \cot(64) } \\ \\ => \frac{ \tan(90 - 64) }{ \cot(64) } \\ \\ => \frac{ \cot(64) }{ \cot(64) } \\ \\ = > 1$

Answer 2

=
$\tan(26) \times \frac{1}{ \tan(64) } \\ = \tan(26 ) \times \frac{1}{ \cot(26) } \\ = 1$