Question

$tan \binom{19\pi}{3}$
values
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Answer 1

SOLUTION

$tan \: \frac{19\pi}{3} \\ = > tan \: 6 \frac{1}{3} \pi \\ \\ = > tan(6\pi + \frac{1}{3} \pi) \\ \\ = > tan \: (3(2\pi) + \frac{1}{3} \pi) \\ \\ = > values \: of \: tan \: x \: repeats \: after \: an \: interval \: of \: 2\pi \: hence \: ignoring \: 3 \times (2\pi) \\ \\ = > tan \: ( \frac{1}{3} \pi) \\ \\ = > tan \: ( \frac{1}{3} \times 180 \degree) \\ \\ = > tan \: 60 \degree \\ \\ = > \sqrt{3}$

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Answer 2

Step-by-step explanation:

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