Question

$\tan( \div 1 + \cot( + \cot( \div 1 - \tan(?) ) ) )$
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Answer 1

Answer:

what the frick, type properly bruh!!!

Answer 2

$tan A)/(1 - cot A) + cot A /(1 - tan A) = (tan A)/[(1 - (1/tan A)] + cot A /(1 - tan A) = (tan2 A)/[(tan A - 1)] + cot A /(1 - tan A) = (tan2 A)/[(tan A - 1)] - cot A /(tan A - 1) = (tan2 A - cot A) / (tan A - 1) = (tan2 A - 1/tan A) / (tan A - 1) = (tan3 A - 1) / [tan A (tan A - 1)] = (tan A - 1)(tan2 A + tan A + 1) / [tan A (tan A - 1)] = (tan2 A + tan A + 1) / tan A = 1 + tan A + cot A = 1 + [(sin A/cosA) + (cos A/sin A)] = 1 + [(sin2 A + cos2 A) / sin A cos A] = 1 + [1 / (sin A cos A)] = 1 + (sec A x cos A) Hence \: proved$