Question

$\tan30 \times sec45 + \tan60 \times \sec30$
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Answer 1

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Answer 2

Answer:

Step-by-step explanation:

$\tan(30) \times \sec(45) + \tan(60) \times \sec(30) \\ = \frac{1}{ \sqrt{3} } \times \sqrt{2} + \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ = \frac{ \sqrt{2} }{ \sqrt{3} } + 2 \\ = \frac{ \sqrt{2} + 2 \sqrt{3} }{ \sqrt{3} }$

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