Question

In a quadrilateral ABCD,AB is parallel to CD and AD=BC= 7 cm.If angle A= 70⁰ then the measure of angle C is

(A)70⁰

(B)100⁰

(C)80⁰

(D)110⁰

Pls answer this question with explanations.....Irrelevant answers will be reported...​

Answer 1

Answer:

here is your answer dear...

70° ( because opposite angles of a parallelogram are equal )

hope it helps you....

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Answer 2

Given, AB∥CD, ∠D=2∠B, AD=b, CD=a

Now, AD=b ∴CM=b

and CD=a ∴AM=a

AB∥CD, thus, AMCD is a parallelogram.

∴∠D=∠AMC

∠AMC=2x

In △MCB

2x=∠MCB+∠x( ∵ Exterior angle is equal to sum of opposite interior angle)

=>∠MCB=x

=>∠MCB=∠B=x

∴MB=MC[As sides opposite to equal angles are equal]

Now, AB=AM+MB

=>AB=a+b