Question

$the \: hcf \: of \: ( {4u}^{2} - {25v}^{2} ) \: and \: ( {6u}^{2} + 15uv) \: is$

PLEASE ANSWER FOR THIS QUESTION. ​

Answer 1

Answer:

(2u + 5v)

Step-by-step explanation:

HCF of (4u^2 - 25v^2) and (6u^2 + 15uv)

formula : (a^2 - b^2) = (a + b) (a - b)

(4u^2 - 25v^2) = (2u)^2 - (5v)^2 = (2u + 5v) (2u - 5v)

6u^2 + 15uv = 3u(2u + 5v)

So the HCF of  (2u + 5v) (2u - 5v) and 3u(2u + 5v) =   (2u + 5v)