plz solve this.
Answers
Answered by
1
Answer:
Answer is 1 It is very simple answer
Answered by
1
Step-by-step explanation:
ANSWER
(x
q−r
)
qr
1
×(x
r−p
)
rp
1
×(x
p−q
)
pq
1
=x
qr
q−r
×x
rp
r−p
×x
pq
p−q
On adding all the powers of x, we get
⇒x
(
qr
q−r
+
rp
r−p
+
pq
p−q
)
=x
pqr
p(q−r)+q(r−p)+r(p−q)
=x
pqr
0
=1
hope it will help you
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