Question

$what \: is \: the \: area \: of \: an \: equilatreal \: triangle \: with \: side \: 2 \: cm$
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Answer 1

Answer:

$Area \: = > \sqrt{3} cm {}^{2}$

Step-by-step explanation:

$Since \: area \: of \: equilateral\: \\ triangle = \frac{ \sqrt{3} }{4} ( side) {}^{2}$

$Here \: side \: = 2 \: cm$

$Therefore \: area \: = \frac{ \sqrt{3} }{4} \times (2) {}^{2} \\ = > \frac{ \sqrt{3} }{4} \times 4 = \sqrt{3} cm {}^{2}$