Math, asked by arnav4257, 10 months ago


what \: is \: the \: remainder \: when \:   {x}^{2}  + 2x + 1 \: is \: divided \: by (x + 1)

Answers

Answered by piyushsp8017
1

Answer:

Please refer to this Attachment...

Hence, the remainder is 0.

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Attachments:

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Answered by Jaat440
1

x{2}  + 2x + 1 \div x + 1 \\  \\  x + 1)x{2}  + 2x + 1(x  + 1\\  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \: x{2}  + x  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  -  \:  \:\:  \:  -  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x + 1 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x + 1 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  -  \:  \:  \:  \:  -  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 0

The remainder is 0

ANSWER

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