Question

$(x + 1) {}^{2} = (x - 3)$
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Answer 1

⊙ QUESTION ⊙

$(x + 1) {}^{2} = (x - 3)$

⊙STEP BY STEP EXPLAINANTION ⊙

=> (x+1)²=(x-3)

=>x²+2x+1=x-3

=>x²+x+4=0

=>This equation has unreal roots.

The roots are complex.

for further solution,

apply,

Shreedharacharya's law.

ans.

Answer 2

Answer:

(x + 1)² = x - 3

=> x² + 1 + 2x = x - 3

=> x² + 2x - x + 1 + 3 = 0

=> x² + x + 4 = 0

Using the Sridhar Acharya formula,

Comparing the equation with ax² + bx + c, we get,

a = 1, b = 1 and c = 4

x = {-b + - √(b² - 4ac)}/2a

= [-1 + - √{(1)² - (4 × 1 × 4)}]/(2 × 1)

= (-1 + - √(1 - 16)}/2

= (-1 +- √(-15)}/2

= (-1 + √(-15)/2 Or (-1 - √(-15)/2

So, the roots of this equation are imaginary numbers.

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