Math, asked by Apurva77, 1 year ago


 {x }^{2}  - 1 - 2y -  {y}^{2}
Factorise....
First correct answer will be marked as brainliest...!!!

Answers

Answered by siddhartharao77
4
Given Equation is x^2 - 1-  2y - y^2

= > x^2 - (y^2 + 2y + 1)

= > x^2 - (y + 1)^2

We know that a^2 - b^2 = (a - b)(a + b)

= > (x - (y + 1))(x + (y + 1))

= > (x - y - 1)(x + y + 1).


Hope this helps!

Apurva77: thanks
siddhartharao77: Welcome
Apurva77: i'd posted one more question do check it out
Answered by Anonymous
6
hay

Dear friend

=> x²-y²-1-2y

=> x² - (y+1)²

=> {x-(y+1)} {x+(y+1)}

Now,

=> (x-y-1) ( x+y+1)





I hope it's help you

Apurva77: sorry but this is not the answer
Anonymous: ok
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