Question

$x {?}^{2} - 12x + 20$
factorise it.​

Answer 1

Answer:

Step-by-step explanation:x^2-12x+20=0

x^2-(10+2)x+20=0

x^2-10x-2x+20=0

x(x-10)-2(x-10)=0

(x-10)(x-2)=0

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Answer 2

Answer:

( x - 10 ) ( x - 2 )

Step-by-step explanation:

$x^{2} -12x+20\\\\=>x^{2} -10x-2x+20\\\\=>x(x-10)-2(x-10)\\\\=>(x-10)(x-2)$

20 has factors 2,10 and 4,5.

2,10 is suitable here.