Question

$x {}^{2} - 2x - 8$
Verify the Zero and the cofficient​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

x = 4 and -2

Step-by-step explanation:

==: x² - 2x - 8 = 0

==: x² - 4x + 2x - 8 = 0

==: x (x - 4) + 2 (x - 4) = 0

==: (x - 4) (x + 2) = 0

x = 4 and -2

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