Question

${x }^{2} + 2y - 1$
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Answer 1

Step-by-step explanation:

${x}^{2} + 2y - 1$

${b}^{2} -4ac = 0$

${2}^{2} - 4×1×1= 0$

D = 0

so, roots = -b ± √b^2-4ac/2a

so, x= -2+0/2 = -1

y= -2-0/2

= -1

the roots are (-1,-1)