Question

$x {}^{2} - 3 \sqrt{3} + 6 = 0 \: factorisation \: method$

Answer 1

Heya !!




X² - 3√3X + 6 = 0




X² - √3X - 2√3X + 6 = 0





X ( X - √3 ) - 2√3 ( X - √3 ) = 0





( X - √3 ) ( X - 2√3 ) = 0




( X - √3 ) = 0 OR ( X - 2√3 ) = 0





X = √3 OR X = 2√3.

Answer 2

x² - 3√3x + 6 = 0

=> x² - ( 2√3 + √3 ) x + 6 = 0

=> x² - 2√3x - √3x + 6 = 0


=> x( x - 2√3 ) - √3( x - 2√3 ) = 0

=> ( x - √3 ) ( x - 2√3 ) = 0


$\mathbf{By \: \: Zero \: \: Product \: \: Rule } \\ \\ x = 2 \sqrt{3} \: \: \: \: or \: \: \: \: x = \sqrt{3}$