Question

$x {}^{2} + 3x + 9 = 0$
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Answer 1

${x}^{2} + 3x + 9 = 0 \\ \\ here \: \\ a = 1 \\ b = 3 \\ c = 9 \\ \\ by \: quadratic \: formula \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2} \\ \\ = > x = \frac{ - 3 + - \sqrt{9 - 4 \times 1 \times 9} }{2} \\ \\ = > x = \frac{ - 3 + - \sqrt{9 - 36} }{2} \\ \\ = > x = \frac{ - 3 + - \sqrt{ - 27} }{2} \\ \\ so \\ x = \frac{ - 3 + \sqrt{27} i}{2} \\ or \\ x = \frac{3 - \sqrt{27} i}{2}$

Answer 2

Hope it will help you ❤ ⤵