Math, asked by RupeshChoudhary, 10 months ago


x {2}  + 4x + 4

Answers

Answered by Anonymous
0

 =  {x}^{2}  + 4x + 4 \\  =  {x}^{2}  + 2x + 2x + 4 \\  = (x + 2)(x + 2) \\  =  {(x + 2)}^{2}

hope it helps you

Answered by anusha3579
0

x^2+4x+4=0

x^2+2x+2x+4=0

x(x+2)2(x+2)=0

x+2 = 0 ( or ) x+2 = 0

x = -2 ( or ) x = -2

this is prime factorization

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