Question

$x {}^{2} - 4x { + 4a}^{2}$
​

Answer 1

Answer:

$2± 2\sqrt{1 - {a}^{2} }$

Step-by-step explanation:

roots are

$\frac{ - b \: ± \sqrt{ {b}^{2} - 4ac} }{2a}$

b= -4

a =1

c=4a²

$= \frac{ 4± \sqrt{16 - 4 \times 1 \times 4 {a}^{2} } }{2}$

$\frac{4 ± 4 \sqrt{1 - {a}^{2} } }{2}$

$= 2± 2\sqrt{1- {a}^{2} }$