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x²+4x+5 = 0
-b±√b²-4ac/2a
=-4±√16-4(1)(5)/2(1)
=-4±√16-20/2
=-4±√-4/(2)
==> -4+√-4/2
and -4-√-4/2
are the roots
-b±√b²-4ac/2a
=-4±√16-4(1)(5)/2(1)
=-4±√16-20/2
=-4±√-4/(2)
==> -4+√-4/2
and -4-√-4/2
are the roots
Answered by
0
Heyaa!! folk
hope this helps u
hope this helps u
saindulakavath:
100% wrong
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