Question

${x}^{2} - (a + b)x + ab = 0$
Solve the problem​

Answer 1

x^2-ax-bx+ab=0

x^2-ax+ab-bx=0

x(x-a)+b(a-x)=0

x(x-a)-b(x-a)=0

(x-a)(x-b)=0

x-a=0

x=a

x-b=0

x=b

I HOPE THIS HELPS YOU AND PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE MARK ME THE BRAINLIEST.

Answer 2

x-a=0

x=a

x-b=0

x=b

PLEASE MARK ME THE BRAINLIEST.