Question

$x ^{2} - \sqrt{3x } - 6 =$

Answer 1

Hey, Here is your answer
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$x ^{2} - \sqrt{3 }x - 6 = 0 \\ \\ {x}^{2} - 2 \sqrt{3} x - \sqrt{3} x - 6 = 0 \\ \\ x(x - 2 \sqrt{3} ) - \sqrt{3}(x - 2 \sqrt{3} ) = 0 \\ \\ (x - \sqrt{3} )(x - 2 \sqrt{3} ) = 0 \\ \\ x - \sqrt{3} = 0 \: \: \: \: or \: \\ x - 2 \sqrt{3} = 0 \\ \\ x = \sqrt{3} \: \: or \: \: 2 \sqrt{3}$
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