Math, asked by tanya30maheshwari, 3 days ago

$x^{2} \sqrt{x} \sqrt[n]{x} x_{123} \pi \leq \\ \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \beta \beta \beta \left \{ {{y=2} \atop {x=2}} \right. \\$

Answers

Answered by uttamkumar1230023

0

Answer:

5658

Step-by-step explanation:

56985687263318521866506558844555566666688552841276437373737373737357376567386576

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