Question

${x}^{2} \times {x}^{2} + \sqrt{256} = 32$
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Answer 1

Answer:

x = 2

Step-by-step explanation:

${x}^{2} \times {x}^{2} + \sqrt{256} = 32 \\ > > \sqrt{256} = 16 < < \\ {x}^{4} + 16 = 32 \\ {x}^{4} = 32 - 16 \\ {x}^{4} = 16 \\ > > 16 = 2 \times 2 \times 2 \times 2 = {2}^{4} < < \\ {x}^{4} = {2}^{4} \\ x = 2$